<PRE><B>Question 1169059</B>
an engineer is to design a rectangular computer screen with a 19-inch diagonal and a 175-square inch area. find the dimensions of the screen to the nearest tenth of an inch
solution 
let length is x and width is y
diagonal square root of (x^2+y^2)=19
x^2+y^2=361
xy=175
(x+y)^2=361+350=711   THAN X+Y=26.66
(X-Y)^2=361-350=11   THAN  X-Y=3.31  BY SOLVING BOTH EQUATION WE WILL GET X=14.988 INCHES 
Y=11.678 INCHES 
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