Question 1169037
.
<pre>

    {{{rate[1]}}} + {{{rate[2]}}} = {{{1/3}}}


    {{{1/x}}}     + {{{1/(x+2)}}} = {{{1/3}}}


    3*(x+2)  + 3x = x*(x+2)

    3x  + 6  + 3x = x^2 + 2x

    x^2 - 4x - 6 = 0


    Solve using the quadratic formula.
</pre>