Question 1169020
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Since you didn't bother to define *[tex \Large x], I can't really answer the question.  The area of a rectangle is the length times the width. Find an answer with two factors, one of which looks like two times the measure of a side of the square plus 9 and the other that looks like the measure of a side of the square minus 6.


																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
*[illustration darwinfish]


I > Ø
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
{{n}\choose{r}}
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