Question 1168992
Line containing A and perpendicular to 6=y+2x, intersects WHERE on 6=y+2x?

{{{6=y+2x}}}
{{{y=-2x+6}}}
slope of given line is {{{-2}}}.  Line perpendicular is slope  {{{1/2}}}.


Look for {{{y-8=(1/2)(x-4)}}}
{{{y=x/2-2+8}}}
{{{y=x/2+6}}}



Intersection Point of these two line?
{{{system(y=-2x+6,and,y=x/2+6)}}}

{{{-2x+6=x/2+6}}}
{{{x=0}}}{{{and}}}{{{y=6}}}


Use Distance Formula to find distance from  (0,6) to (4,8).