Question 1168993
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<pre>

From the second equation, you express  y = 4-x  and substitute it into the first equation, replacing "y" there


    4 - x = -x^2 + 2x + 4.


Now you just have one single quadratic equation.


Reduce it to the standard form quadratic equation, collecting all the terms in one side (on the left, in this case)


    x^2 - 3x = 0.


Solve by factoring


    x*(x-3) = 0.


The roots are x= 0  and  x= 3.


The solutions to the system are  (x,y) = (0,4)  and  (x,y) = (3,1).    <U>ANSWER</U>


You can check the answer by substituting the found solution values of x and y into the original system.
</pre>

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&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Systems-of-equations/Solving-the-system-of-alg-eqns-of-deg2-deg1.lesson>Solving systems of algebraic equations of degree 2 and degree 1</A> 

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