Question 1168890

Did I also subtract the below equations correctly?


3a
a+4
−
(2a2−16a
a2−16)=

a3+8a2+16a
a3+4a2−16a−64=


a(a+4)(a+4)
(a+4)(a+4)(a−4)=

a
a−4

Thank you
<pre>Your simplification doesn't seem to make sense.
However, your final answer is CORRECT, considering that what you have is: {{{3a/(a + 4) - (2a^2 - 16a)/(a^2 - 16)}}}
By the way, you need to present these problems better. This one should be written like this: 3a/(a + 4) - (2a^2 - 16a)/(a^2 - 16)