Question 1168871
mean = 0 degrees centigrade
standard deviation is 1 degree centigrade.


probabilit y of obtaining a reading between -2.19 degrees centigrade and -.419 degrees centigrade is ?????


use the following calculator.


<a href = "https://stattrek.com/online-calculator/normal.aspx" target = "_blank">https://stattrek.com/online-calculator/normal.aspx</a>


this calculator works similar to the tables, i.e. it just gives you the area to the left of the z-score or x-score and you have to figure out the rest, i.e. like finding the area to the right of the z-score by finding the area to the left of the z-score and then subtracting it from 1.


for the low score, set p(x<X) to -2.19.
calculator says probability is .014.


the the high score, set p(x<X) to -.419
calculate says probability is 0.338


subtract the smaller area from the larger area to get:
area between -2.19 and -.419 = .338 minus .014 = .324


visually, this looks like this:


<img src = "http://theo.x10hosting.com/2020/110303.jpg" >


the different values you see are due to rounding differences between the calculators used.


the calculator that gave you the visual display can be found at:


<a href = "http://davidmlane.com/hyperstat/z_table.html" target = "_blank">http://davidmlane.com/hyperstat/z_table.html</a>