Question 108821
[(3y^2-12) /(4y^2+4y+4)] / [(y^3-2y^2) / (Y^2+2y)]

Factor where you can:

= [3y(y-4) / 4(y^2+y+1)] / [y^2(y-2) / y(y+2)]

Cancel any factor common to a numerator and a denominator such as "y":

= [3y(y-4) / 4(y^2+y+1)] / [y(y-2) / (y+2)]

Invert the denominator and multiply:

= [3y(y-4) / 4(y^2+y+1)] * [(y+2)/ y(y-2) ]

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Cancel any factor common to a numerator and a denominator such as "y":

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= [3(y-4)(y+2)] / [4(y^2+y+1)(y-2)]

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Cheers,
Stan H.