Question 1168766
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<pre>
It is the binomial type probability distribution.


The number of trial n= 190; the probability of the success trial is  0.015,  and the number of success trial k = 2. 


P = {{{C[190]^2*0.015^2*(1-0.015)^(190-2)}}} = {{{((190*189)/(1*2))*0.015^2*0.985^188}}} = 0.235711.     <U>ANSWER</U>
</pre>

Solved.


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