Question 1168770
Try accounting for the pure acid.


{{{0.1*5+0.2x=0.18(5+x)}}}

{{{0.5+0.2x=0.18x+0.18*5}}}

{{{0.02x=0.18*5-0.5}}}

{{{0.02x=0.4}}}


{{{highlight(x=20)}}}