Question 1168727
length of edge of base, x


Given the volume, h for height, {{{hx^2=8}}}.


Also given, {{{h<x}}}.

-
-


Using the given h and x relationship, {{{h<x}}}
and substituting for {{{h=8/x^2}}} from the volume equation,

{{{8/x^2<x}}}-----and now solve for x.

{{{8/x^2-x<0}}}

{{{8/x^2-x(x^2/x^2)<0}}}


{{{(8-x^3)/x^2<0}}}----this must mean  {{{negative/positive<0}}};

need to have {{{8-x^3<0}}}

{{{8<x^3}}}

{{{2<x}}}


x must be greater than 2.