Question 1168707
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<pre>

The pdf function is  f(x) = {{{(3/4)*(1-x^2)}}}  on the interval  [-1,1].


The cdf function is  antiderivative  F(x)  of  f(x)  such that F(-1) = 0.


So, the antiderivative is  F(x) = {{{(3/4)*(x - x^3/3) + C}}} = {{{(3/4)x}}} - {{{x^3/4}}} + {{{C}}},     (1)


where C is the constant such that  F(-1) = 0.


From this condition,  you have this equation, substituting x= -1 into the formula (1) 


    {{{(3/4)*(-1)}}} - {{{(-1)^3/4}}} + {{{C}}} = 0,    or

    {{{-3/4 + 1/4 + C}}} = 0,                  or

    {{{-1/2 + C}}} = 0,

which gives

    C = {{{1/2}}}.


So, your antiderivative, or cdf function is

    F(x) = {{{(3/4)x}}} - {{{x^3/4}}} + {{{1/2}}}.


Thus I complete calculating the needed cdf function.
</pre>

Now my short COMMENT regarding your solution.


<pre>
    Your solution was INCORRECT.

    You incorrectly found the cdf function,

    because in integrating process you forgot about the constant term "C"

                                   and forgot to satisfy the condition F(-1) = 0 for your cdf function.
</pre>


I stop at this point leaving to complete the part 2 of the problem to you.