Question 1168672
I'm assuming you mean N(t) = 2800/(5+13.5e^−0.038t)
The initial population is N(0) = 2800/(5+13.5e^0) = 2800/(5+13.5) = 1513.51 -> 1514
As t→∞, the negative exponential goes to 0. Thus the maximum population is = 28000/5 = 5600
N(10) = 1967.38 -> 1967