Question 108754
A family made a trip by car. 
They traveled 1312 km in 3 days. 
On the 2nd day, they traveled 2 times the number of km from the 1st day. 
On the 3rd day, they traveled 98 km less than the 2nd day. 
Find the distance traveled every day.
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x= first day travel
2x=2nd day
2x-98=3rd day
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x+2x+2x-98=1312
5x=1312+98
5x=1410
x=282
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first day = 282
2nd day= 2(282)=564
3rd day = 564-98=466
:)