Question 108820
I'm a litle confused here. 
Should your function f(x) look like this.
{{{f(x)=5x^2-3x+1}}}
{{{f(-2)=5(-2)^2-3(-2)+1}}}
{{{f(-2)=5(4)-3(-2)+1}}}
{{{f(-2)=20+6+1}}}
{{{f(-2)=27}}}
Correct answer. 
However you went from 10^ in the second line of your solution to 20 in the third line???