Question 1168474
half-interval is t(0.99, df=27)*s/sqrt(n)
=2.47*7.3/sqrt(28)
=3.41. This is the margin of error.
so the 98% CI is mean +/- 3.41
this is (27.8, 34.6) min the 98% CI

We don't know the exact mean for the commute interval, but we are 98% confident it lies in this interval.
If we took multiple samples of 28, 98% of them would contain the true mean, but we wouldn't know which 98. 

This is A.  CIs discuss parameters.