Question 1168478
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{{{2^6}}} = 64 different toppings (including one "zero" topping).   <U>ANSWER</U>



<U>EXPLANATION</U>


I will give you two explanation.


    1)  Any set of n elements has {{{2^n}}}  different subsets (including the empty set and improper set).


    2)  Any particular topping can be included or excluded, giving two different options.

        Therefore, the total number of all possible combinations is  {{{2^6}}}.
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