Question 1168369
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The problem in the post is given in a very uncertain mode/formulation.


I am not about more accurate wording, but about making a sense, in general.


Clearly, to be (to become) a real Math problem, it should be re-formulated.


It could be interpreted in this way.



<pre>
    9 different items should be distributed among n persons.

    Each person can get one or more items, or can get no items, at all.

    Find the number of different possible distributions.
</pre>


I don't know if my interpretation is exactly what you keep in your mind.


But it is very nice Math problem from combinatorics.



<pre>
1-st item can go to any of n persons (n options).

2-nd item can go to any of n persons (n options).

3-rd item can go to any of n persons (n options).

. . . . . . . . . . . . . . . . . . . . . . . . . 


9-th item can go to any of n persons (n options).


In all, there are  {{{n^9}}}  ways to distribute 9 items among n persons under given conditions.    <U>ANSWER</U>
</pre>

Solved.