Question 1168261
xy = -40
Let y = -40/x
<pr>
x + y = -3
<pr>
x - 40/x = -3
<pr>
x²/x - 40/x = -3
<pr>
(x² - 40)/x = -3
<pr>
x² - 40 = -3x
<pr>
x² + 3x - 40 = 0
<pr>
(x - 5)(x + 8) = 0
<pr>
x = 5 and x = -8
<pr>
If x = 5, y = -8.  
If x = -8, y = 5.
<pr>
So, the two integers are 5 and -8.