Question 1168109
p1=0.364
p2=0.2375

the difference is 0.1265
the SE is sqrt (0.364*0.636/1500)+(0.2375*0.7625/2000). this is sqrt (p1*(1-p1)/n2+p2(1-p2)/n2))
=0.0156
the CI half-interval is 1.96*0.0156=0.0306
this is added to and subtracted from the mean to get (0.0959, 0.1571)

Where you round and how much determines that last two decimal places.