Question 1168099
perpendicular lines have slope products that are negative reciprocals.
the perpendicular line has slope of -2/3.
point slope formula y-y1=m(x-x1), (x1, y1) is point
y-1=(-2/3)(x+6)
y=(-2/3)x-3

{{{graph(300,300,-10,10,-10,10,(3/2)x+1,(-2/3)x-3)}}}