Question 1168083
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For any right triangle, the median drawn to hypotenuse, has the length HALF of the hypotenuse.


Therefore, in your problem the hypotenuse length is  2*30.5 = 61 units.


Hence, the other leg is  {{{sqrt(61^2-11^2)}}} = {{{sqrt(3600)}}} = 60 units.


Then the area of the triangle is  {{{(11*60)/2}}} = 11*30 = 330 square units.
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Solved.