Question 1168041
ax^2+bx+c=0
vertex=-b/2a=-5
s0 -b=-10a
b=10a
f(-5)=-7
start with a=1 b=10
x^2+10x+c=0
when x=-5, y=7
so 25-50+c=-7 and c=18
so x^2+10x+18=0
{{{graph(300,300,-10,10,-10,10, x^2+10x+18)}}}