Question 1168030
Ambiguous.
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{{{x/4x-8- 2/3x+6 = 4x^2-2x+9/12x^2−48}}}
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After some emails:
{{{x/(4x-8)- 2/(3x+6) = (4x^2-2x+9)/(12x^2-48)}}}
{{{x/(4(x-2))- 2/(3(x+2)) = (4x^2-2x+9)/(12(x^2-4))}}}
Multiply by 12
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{{{3x/(x-2)- 8/(x+2) = (4x^2-2x+9)/(x^2-4)}}}
Multiply by (x^2-4)
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{{{3x*(x+2)- 8*(x-2) = (4x^2-2x+9)}}}
{{{3x^2+6x- 8x+16 = (4x^2-2x+9)}}}
{{{3x^2 - 2x + 16 = 4x^2-2x+9)}}}
{{{16 = x^2+9)}}}
x^2 = 7
{{{x = sqrt(7)}}}
{{{x = -sqrt(7)}}}