Question 1167812
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vertex of a quadratic is at (3, 16) and one of the zeros is at (-1, 0)
What is the coordinate of the other zero?
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If want vertical symmetry axis, {{{y=a(x-h)^2+k}}}
{{{y=a(x-3)^2+16}}}
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{{{0=a(-1-3)^2+16}}}
{{{16a+16=0}}}
{{{a=-1}}}
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{{{highlight(y=-(x-3)^2+16)}}}


FOR THE OTHER ZERO:   symmetry axis x=3, is 4 units away from one of the zeros given  (-1,0).  The OTHER zero is at x=7.  <b>Other zero is  (7,0)</b>.