Question 108670
Let a be the first integer, and let b be the second.

We know the following facts.

{{{
a=2b+3
}}}
{{{
ab=27}}}

we can solve by substitution. Since a is 2b+3 we can subsitute that into the second equation.

{{{
b(2b+3)=27
}}}
{{{2b^2+3b-27=0}}}
{{{(2b+9)(b-3)=0}}}

So, be is 2/9 or 3. But, 2/9 is not an integer, so b=3. a=2b+3 which is 9.