Question 1167696
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Prove by exhaustive cases.


Assume P, then P v R follows directly


Assume ~P, then Q follows from P v Q, but if Q, then ~Q v R implies R and therefore P v R.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
*[illustration darwinfish]


I > Ø
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
{{n}\choose{r}}
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