Question 1167592
<br>
Batman flies for 3 hours more than Wonder Woman.  So<br>
let t = hours Wonder Woman flies
then t+3 = hours Batman flies<br>
There is no need for variables to represent the distances, because when Wonder Woman catches up to Batman their distances are the same.  However, since that is apparently what you are doing in class....<br>
D1 = Batman's distance (t+3 hours at 240 mph) = 240(t+3)
D2 = Wonder Woman's distance (t hours at 600 mph) = 600(t)<br>
The two distances are the same:<br>
{{{240(t+3) = 600(t)}}}
{{{240t+720 = 600t}}}
{{{720 = 360t}}}
{{{t = 2}}}<br>
ANSWER: Wonder Woman catches up with Batman after t=2 hours.<br>
CHECK:
Batman t+3 = 5 hours at 240 mph = 5(240) = 1200 miles
Wonder Woman t = 2 hours at 600 mph = 2(600) = 1200 miles<br>