Question 1167302
<pre>
Since the die has 6 faces, there are (6)(6)(6)(6) = 6<sup>4</sup> = 1296 possible
sequences.

From these 1296 sequences we must eliminate all sequences which fail. These are
all the ways in which all 4 rolls are 1,2,3, or 4.  There are (4)(4)(4)(4) =
4<sup>4</sup> = 256 sequences which fail.

So 1296-256 = 1040 sequences contain at least one number greater than 4? 

Answer = 1040

Edwin</pre>