Question 1167388
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An equation of a straight line in a coordinate plane which has the slope  m  and passes through the given point  P = (a,b)  is 


        y - b = m*(x-a).                      (1)



<pre>
Simply substitute the given data into equation &nbsp;(1), &nbsp;and you will get

    y-2 = (-5/6)*(x-6).         (2)


It is the equation in the &nbsp;"slope intercept form".


If you want to get the standard form equation, &nbsp;simplify&nbsp; (2):

   6y-12 = -5x + 30,  &nbsp;&nbsp;or, &nbsp;equivalently,  &nbsp;&nbsp;5x + 6y = 30 + 12,

or, &nbsp;finally, &nbsp;&nbsp;5x+6y = 42. 
</pre>

Solved.


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See the lesson in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/geometry/Equation-for--a-straight-line-having-a-given-slope-and-passing-through-a-given-point.lesson>Equation for a straight line having a given slope and passing through a given point</A>