Question 1167362
this is a binomial with n=11 p=0.52 and want 0 to 4.
Can do this by doing each calculation from 0 to 4 (e.g.,for p(4) it is 11C4*0.52^4*0.48^7) (=0.1416) p(0) 0.48^11=0.0003
or 
binomcdf(11,0.52,4)=0.2312

mean is 5.72 and variance is 2.76 (so sd 1.66), so approximately less than 1.22/1.66 sd and that gives a probability of 0.2327, so rough approximation a very reasonable check.