Question 1167303
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<pre>

Let r be the rate of the slower jet;  then the rate of the faster jet is (r+15) mph.


The total separating distance is

    5r + 5*(r+15),


and it is equal to 6730.  So your base equation is

    5r + 5*(r+15) = 6730.


Simplify and find r

    5r + 5r + 75 = 6730

    10r          = 6730 - 75 = 6655

      r                      = 665.5.


<U>ANSWER</U>.  The rate of the slower jet is  665.5 mph.

         The rate of the faster jet is  665.5 + 15 = 680.5 mph.


<U>CHECK</U>.  5*665.5 + 5*680.5 = 6730  separating distance in 5 hours.   ! Correct !
</pre>

Solved.


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For simple Travel & Distance problems, &nbsp;see introductory lessons 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/travel/Travel-and-Distance-problems.lesson>Travel and Distance problems</A>  

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/travel/Travel-and-Distance-problems-for-two-bodies-moving-toward-each-other.lesson>Travel and Distance problems for two bodies moving in opposite directions</A> 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/travel/Typical-catching-up-Travel-and-Distance-problems.lesson>Travel and Distance problems for two bodies moving in the same direction (catching up)</A>

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