Question 1167133
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            I came to bring the correct solution.



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{{{4x^2+12x+4y^2+16y=11}}}


{{{4(x^2+3x+y^2+4y)=11}}}


{{{4(x^2+3x+(3/2)^2+y^2+4y+4)=11+4(3/2)^2+16}}}


{{{4((x+3/2)^2+(y+2)^2)=27+4(3/2)^2}}}


{{{4((x+3/2)^2+(y+2)^2)=27+9}}}


{{{4((x+3/2)^2+(y+2)^2)=36}}}


{{{highlight((x+3/2)^2+(y+2)^2)}}} = {{{9)}}}


Circle centered at  (-1.5,-2) and radius of {{{3}}}  units.    <U>ANSWER</U>
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