Question 1167058
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four consecutive odd integers such that 6 times the sum of the first and third is 3 more than 5 times the opposite of the fourth.
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{{{system(Integers,n,n+2,n+4,n+6)}}}


{{{6(n+n+4)=5(-n-6)+3}}}-------equivalent to yours, so all you need is do the arithmetic.


RESULT:    -3, -1, 1, 3