Question 1166985
<font face="Times New Roman" size="+2">

The area of a regular hexagon given the perimeter and apothem is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ =\ \frac{Pa}{2}]


But in a regular hexagon the perimeter consists of six equal sides, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ =\ \frac{6sa}{2}\ =\ 3sa]


Plug in your given values for *[tex \Large A] and *[tex \Large a] and solve for *[tex \Large s] 


																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
*[illustration darwinfish]


I > Ø
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
{{n}\choose{r}}
</font>