Question 108549
P=13+45lnx represents the percentage of inbound e-mail in the U.S. that is considered spam, where x is the number of years after 2000.
P(2003) = 13 + 45 ln(2003-2000)
P(2003) = 13 + 45 ln(3)
P(2003) = 13 + 45*1.098612289...
P(2003) =  62.43755299...  or 62.4%
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Cheers,
Stan H.