Question 1166857
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P(G OR E)....<br>
(1) an elementary solution<br>
Count the number that are either green (3), or are not green (i.e., are yellow) and are even (2):
P(G OR E) = 3/7 + 2/7 = 5/7<br>
(2) by a more sophisticated method<br>
Count the number that are green (3), add the number that are even (3), then subtract the number that are both green and even (1) (since you have counted them twice):
P(G OR E) = P(G) + P(E) - P(G AND E) = 3/7 + 3/7 - 1/7 = 5/7<br>
(3) by yet a different method<br>
Count the number that are NOT green AND NOT even (i.e., that are NEITHER green NOR even = that are yellow and odd (2)), and subtract that from the total (7):
P(G OR E) = 1 - P(NOT(G) AND NOT(E)) = 7/7 - 2/7 = 5/7<br>