Question 108312
One employee travels for 4 days and 4 nights and is allotted $480 
That's 4 rooms and 12 meals
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while another employee travels for 3 days and 2 nights and is allotted $270.
That's 2 rooms and 9 meals
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a) Give the system of equations for solving this situation.
1st Equation: 4r+12m = 480
2nd Equation: 2r+9m  = 270
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b) Find the amount allowed for a hotel room and daily food expenses
1st Eq: r + 3m = 120
r = 120-3m
Substitute into 2nd Eq to solve for m:
2(120-3m)+9m = 270
240-6m+9m = 270
3m = 30
m = 10 ($10 for each meal)
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Substitute into r = 120-3m to solve for r:
r = 120-3*10
r = $90 ($90 allowed for a room)
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Cheers,
Stan H.