<PRE><B>Question 1166823</B>
Only two hints:

In 1200 seconds, the two vehicles are {{{22(m/s)*1200*s=26400*meters}}} apart.

The approach rate of the two cars is  {{{28-22=6}}}, in {{{meters/second}}}.


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Handle the formula properly.  Look carefully at your (single) step.

{{{v=d/t}}}, if v is for speed, d is for distance, t is for time.
If you solve this for t, then what will you show?


Now if you have v=6 in meters per second, and d=26400 meters, then, you should understand clearly how to find the time for the catch-up.
-
{{{t=d/v}}}

{{{t=26400/6}}}-------and if you are watching the units carefully, you see this is  4400 seconds.  In HOURS this will be  about 1.222 hours.
1 hour 13 minutes</PRE>