Question 1166806
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -3\ +\ 4(6x\,-\,11)\ =\ x\ -\ (6x\ +\ 15)]


Distribute the 4 across *[tex \Large 6x\ -\ 11].  Distribute the -1 across the *[tex \Large 6x\ +\ 15].  Sum the constant terms in the LHS and then add the additive inverse of that sum to both sides.  Sum the first degree terms in the RHS and then add the additive inverse of that sum to both sides.  Sum the first degree terms in the LHS and the constant terms in the RHS.  Divide the RHS by the coefficient on the variable in the LHS.

																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
*[illustration darwinfish]


I > Ø
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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