Question 1166783
Finding the minimum-----------------


{{{y=0.001x^2-x+600}}}
{{{y=0.001(x^2-1000x)+600}}}
{{{y=0.001(x^2-1000x+(1000/2)^2)+600-(0.001)(1000/2)^2}}}
{{{y=0.001(x-500)^2+600-(0.001)(500)^2}}}
The minimum C will occur for {{{highlight(x=500)}}}.


You can find the value for C at its minimum using either the original function or the last equation.


{{{C(500)=0.001*500^2-500+600}}}
{{{250000*0.001+500}}}
{{{250+500}}}
{{{highlight(750)}}}