Question 1166754
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Use the Midpoint Formulas to find the midpoint of the segment.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  x_m\ =\ \frac{x_1\,+\,x_2}{2}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  y_m\ =\ \frac{y_1\,+\,y_2}{2}]


Use the Slope Formula to find the slope of the line containing the given segment:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  m\ =\ \frac{y_2\,-\,y_1}{x_2\,-\,x_1}]


Calculate the negative reciprocal of the slope of the line containing the given segment which is the slope of a line perpendicular to the segment.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  m_{perp}\ =\ -\frac{1}{m}]


Use the Point-Slope form with *[tex \Large (x_m,y_m)] and *[tex \Large m_{perp}] to write the desired equation.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_m\ =\ m_{perp}(x\ -\ x_m)]


Rearrange into Slope-Intercept form:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ mx\ +\ b]

																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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