Question 5927
1. There are 6 possibilities to get 5 of a kind on 5 regular dices, i.e. all 1, all 2, all 3, all 4, all 5, and all 6. Each one has a probability of 1/6^5. Therefore, total prob. = 6/6^5 = 1/6^4 = 1/1296.

2. We choose 2 dices among 5 (5C2), 1 value among 6 to place on those 2 dices (6C1), then we choose 2 dices from the rest 3 (3C2), and again 1 value from rest 5 to place on those 2 dices (5C1), and lastly 1 value among rest 4 to put on the last dice (4C1)
Total count = 5C2 * 6C1 *3C2 * 5C1 * 4C1 = 7200
Prob = 7200/6^5 = 25/27