Question 1166630
x hours going
9-x hours returning
time to go 1110 miles is 1110/s1, where s1 is speed of jet
time to go 1110 miles is 1110/s2, where s2 is speed of jet

so x=1110/s1
9-x=1110/s2
1110=s1x
1110=s2(9-x)
therefore, s1x=s2(9-x)
but s1=2s2
so 2s2x=s2(9-x)
and 2x=9-x
and 3x=9 
so x=3 hours going there with speed 1110/3=370 mph in jet
and 6 hours returning at 1110 miles or 185 mph in smaller plane.