Question 1166545
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The total area is 200 times 25 square feet.  If he is 82% done, he has 18% remaining. So the amount remaining is *[tex \Large 0.18\,\cdot\,200\,\cdot\,25].  Let's call that quantity *[tex \Large R].


If *[tex \Large x] is the dimension of the width of the strip mowed, then the dimensions of the unmowed portion must be *[tex \Large 200\,-\,2x] and *[tex \Large 25\,-\,2x], so the area of the unmowed portion which we know has a value of *[tex \Large R] must be:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (200\,-\,2x)(25\,-\,2x)\ =\ R]


So all that is left is to calculate the value of *[tex \Large R], expand the product of the two binomials, put the quadratic into standard form, and solve for *[tex \Large x]

																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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