Question 1166548
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The difference of the dimensions of the picture is 5 - 4 = 1 inch.


Since the frame is of uniform width, the difference of the outer dimensions of the frame is 1 inch, too.


The area of 110 square inches of the frame and the picture together 
is the product of the numbers 10 and 11 with the difference 1 unit.


Therefore, the outer dimensions of the frame are 10 and 11 inches.


It implies that the width of the frame is  {{{(11-5)/2}}} = {{{6/2}}} = 3 inches.    <U>ANSWER</U>
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Solved / (mentally)