Question 1166503
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A direct relationship is modeled by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ Y\ =\ kX]


So if the weight on earth is represented by *[tex \Large W_e] and *[tex \Large W_m] represents weight on the moon for the same object, and they are directly related, the following must hold:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ W_e\ =\ kW_m]


We are given that 161.47 lb on earth corresponds to 26.45 lb on the moon, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 161.47\ =\ 26.45k]


Solve for *[tex \Large k], form the specific relation using the correct value of k, substitute 264.12 lb for *[tex \Large W_e] and then solve for *[tex \Large W_m].  You should round your answer to two decimal places after ALL calculations have been completed.

																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">


I > Ø
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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