Question 1166421
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The *[tex \Large x]-intercept of *[tex \Large Ax\ +\ By\ =\ C] is given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ Ax\ +\ 0y\ =\ C]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ \frac{C}{A}]


Therefore, the *[tex \Large x]-intercept is the point *[tex \Large (a,0)] where *[tex \Large a\ =\ \frac{C}{A}].


The *[tex \Large y]-intercept of *[tex \Large Ax\ +\ By\ =\ C] is given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 0x\ +\ By\ =\ C]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ \frac{C}{B}]


Therefore, the *[tex \Large y]-intercept is the point *[tex \Large (0,b)] where *[tex \Large b\ =\ \frac{C}{B}].

																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">


I > Ø
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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