Question 1166419
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<pre>

(a)  8.



(b)  60%,  or  0.6.



(c)  {{{C[8]^5*0.6^5*(1-0.6)^(8-5)}}} = {{{((8*7*6)/(1*2*3))*0.6^5*0.4^3}}} = 0.278692.



(d)  It is the complement probability to the event that NO ONE of the businesses has a website.

     This complementary probability is  1 - {{{0.4^8}}} = 0.999345.
</pre>

Solved.  &nbsp;&nbsp;&nbsp;&nbsp;//  &nbsp;&nbsp;All questions are answered.


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To see many other solved problems on binomial distribution, see the lessons

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Probability-and-statistics/Solving-problems-on-Binomial-distribution-manually.lesson>Simple and simplest probability problems on Binomial distribution</A> 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Probability-and-statistics/Typical-binomial-distribution-probability-problems.lesson>Typical binomial distribution probability problems</A> 

in this site.