Question 108217
carol,ava and cindy swim at a public pool each day . one day carol swam twice as many laps as ava and cindy swam three more laps than ava. if the women swam 27 laps together, how many laps did each swim?
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x=carol
y=ava
z=cindy
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x=2y
z=y+3
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x+y+z=27
2y+y+y+3=27
4y+3=27
4y=27-3
4y=24
y=6
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So Ava swam 6 laps
Carol = 2(6)=12
Cindy=6+3=9
:)